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Question

To construct a triangle ABC in which B=60,C=45 and AB + BC + AC = 12 cm

The steps of construction are:
Step 1: Draw a line segment XY=12 cm
Step 2: At X, construct an angle of 60
and at y construct an angle of 45
Step 3: Bisect these angles. Let bisector of these angles intersect at point A
Step 4 will be


A
Draw perpendicular bisector PQ of XA to intersect XY at B and RS of YA to intersect XY at C
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B
Draw perpendicular bisector PQ of XB to intersect XY at B and RS of YC to intersect XY at C
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C
Join AB and AC to obtain required ΔABC
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D
Bisect these angles.Let bisector of these angles intersect at point A
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Solution

The correct option is A Draw perpendicular bisector PQ of XA to intersect XY at B and RS of YA to intersect XY at C
Step 4: Draw perpendicular bisector PQ of XA to intersect XY at B and perpendicular bisector RS of YA to intersect XY at C.
Then join points A, B and C.
ΔABC is the required triangle.

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