Question

To construct a triangle ABC in which $\angle B={60}^{\circ },\angle C={45}^{\circ }$ and AB + BC + AC = 12 cm

The steps of construction are:
Step 1: Draw a line segment XY=12 cm
Step 2: At X, construct an angle of ${60}^{\circ }$ and at y construct an angle of ${45}^{\circ }$
Step 3: Bisect these angles. Let bisector of these angles intersect at point A
Step 4 will be

• A. Draw perpendicular bisector PQ of XA to intersect XY at B and RS of YA to intersect XY at C
• B. Draw perpendicular bisector PQ of XB to intersect XY at B and RS of YC to intersect XY at C
• C. Join AB and AC to obtain required $\Delta ABC$
• D. Bisect these angles.Let bisector of these angles intersect at point A

Answer 1

The correct option is A Draw perpendicular bisector PQ of XA to intersect XY at B and RS of YA to intersect XY at C

Step 4: Draw perpendicular bisector PQ of XA to intersect XY at B and perpendicular bisector RS of YA to intersect XY at C.
Then join points A, B and C.
$\Delta ABC$ is the required triangle.