wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

To construct a triangle similar to given ΔABC with its sides 35 of that of ΔABC, a ray BX is drawn at acute angle with BC. If we mark points B1,B2,B3,.... at equal distances from B along BX, then point to be joined in next step is?

A
B3 to point C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
B4 to point C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
B5 to point C
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
B6 to point C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C B5 to point C
Suppose PQB is the required triangle.
BQ=35×BCPQ=35×(BQ+QC)5BQ=3BQ+3CQ2BQ=3CQ, i.e, BQCQ=32
Therefore, Q divides BC in ratio 3:2.
Hence, after drawing the ray BX, the next step will be to join the last point, i.e, B5 to point C, and then draw B3Q parallel to B5C to obtain the point Q.

595619_452552_ans.png

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Constructing Similar Triangles
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon