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Question

To construct a triangle similar to given ΔABC with its sides 35 of that of ΔABC, a ray BX is drawn at acute angle with BC. If we mark points B1,B2,B3,.... at equal distances from B along BX, then point to be joined in next step is?

A
B3 to point C
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B
B4 to point C
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C
B5 to point C
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D
B6 to point C
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Solution

The correct option is C B5 to point C
Suppose PQB is the required triangle.
BQ=35×BCPQ=35×(BQ+QC)5BQ=3BQ+3CQ2BQ=3CQ, i.e, BQCQ=32
Therefore, Q divides BC in ratio 3:2.
Hence, after drawing the ray BX, the next step will be to join the last point, i.e, B5 to point C, and then draw B3Q parallel to B5C to obtain the point Q.

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