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To construct ...

Question

To construct an angle ∠PQR = 60° with base PQ = 12 in (Scale : 1 cm = 4 in) the following steps are followed:

Step 1: ?

Step 2: Place the compass at P and draw an arc to cut segment PQ at F.

Step 3: Place the compass pointer at F and draw an arc to cut the arc drawn earlier at E.

Step 4: Join PE. This gives us ∠P = 60°.

Choose the missing step from the given options below.

Draw a line segment PQ of length 3 cm.

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Draw a line segment PQ of length 5 cm.

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Draw a line segment PQ of length 6 cm.

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Draw a line segment PQ of length 4 cm.

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Solution

The correct option is C Draw a line segment PQ of length 6 cm.
The scale is 1 cm = 4 in.

∴ The length of base PQ will be: 12 in = 3 cm.

So, Step 1 will be: 'Draw a line segment PQ of 3 cm.'

The final figure is:

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Similar questions

Q. Which of the following steps is INCORRECT while constructing an angle of

60^{o}

?
Step-1 : Draw a line EF and mark a point O on it.
Step-2 : Place the pointer of the compass at O and draw an arc of convenient radius which cuts the line EF at point P.
Step-3 : With the pointer at A (as centre) now draw an arc that passes through O.
Step-4 : Let the two arcs intersect at O. Join OQ. We get

∠

QOP whose measure is

60^{o}

Q. Which of the following step(s) is/are incorrect while constructing an angle of

120^{o}

?
Step-

1

: Draw a ray AB.
Step-

2

: With A as centre, draw an arc of any convenient radius which cuts AB at C.
Step-

3

: With C as centre and same radius, draw an arc which cuts the arc drawn in Step-

2

at point D.
Step-

4

: With D as centre and same radius, draw an arc which cuts the arc drawn in Step-

3

at point E.
Step-

5

: Join AE and produce it to point F. We get

∠

FAB whose measure is

120^{o}

The steps to construct $60^{\circ}$ angle is given below. Arrange these steps in the correct sequence.

1. Taking O as centre, draw an arc of any size to cut OA at B.

2. Draw a line segment OA of any suitable length.

3. Join OC and produce it to any point D.

4. With B as centre draw another arc of the same size to cut the previous arc at C.

Q. PQRS is a quadrilateral. Measure of PQ = 2.8 cm, QR = 3.1 cm, RS = 2.6 cm and SP = 3.3 cm and

∠

SPQ = 60°. The steps of construction are as follows. What can be the missing step?

Step 1:
Draw a line segment PQ of length 2.8 cm.
Step 2 :
Construct an angle 60° at the point P and extend the line.
Step 3:
Draw an arc of 3.3 cm by taking P as the centre. Let the intersecting point be S.
Step 4: ?
Step 5:
Let the intersecting point of arcs be R. Connect R, to S and Q. PQRS is hence constructed.

Follow the following steps of constructions:

1) Draw a line segment OA.

2) With O as center and a short radius, draw an arc that cuts OA at B.

3) With B as center and the same radius (as in step 2), draw an arc that cuts the first arc at C.

4) With C as center and the same radius (as in step 2), draw an arc that cuts the first arc at D.

5) With C and D as centers, draw two arcs with equal radii such that they intersect at E.

6) Join O and E. What’s the measure of $∠ A O E$ ?

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The correct option is C Draw a line segment PQ of length 6 cm.The scale is 1 cm = 4 in. ∴ The length of base PQ will be: 12 in = 3 cm. So, Step 1 will be: 'Draw a line segment PQ of 3 cm.' The final figure is:

The correct option is C Draw a line segment PQ of length 6 cm.
The scale is 1 cm = 4 in.

∴ The length of base PQ will be: 12 in = 3 cm.

So, Step 1 will be: 'Draw a line segment PQ of 3 cm.'

The final figure is: