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Addition of Odd Numbers to Get Squares

To count a de...

Question

To count a decimal number sequence from 0 to 512, we wish to design a counter. For this counter the number of flip-flops required are

A

9

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B

10

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C

11

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D

8

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Solution

The correct option is B 10
From 0 to $(511)_{10}$ total number of decimal numbers are 512, so for this count we require $(2^{9} = 512)$ 9 flip-flops.

Hence,9+1 = 10 flip-flops are required to count from 0 to 512.

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