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Question

To count a decimal number sequence from 0 to 512, we wish to design a counter. For this counter the number of flip-flops required are

A
10
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B
11
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C
8
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D
9
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Solution

The correct option is A 10
From 0 to (511)10, total number of decimal numbers are 512, so for this count, we require (29=512) 9 flip-flops.

Hence,9+1 = 10 flip-flops are required to count from 0 to 512.

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