Question

To count a decimal number sequence from 0 to 512, we wish to design a counter. For this counter the number of flip-flops required are

• A. 10
• B. 11
• C. 8
• D. 9

Answer 1

The correct option is A 10

From 0 to $(511{)}_{10}$, total number of decimal numbers are 512, so for this count, we require $(2^9=512)$ 9 flip-flops.

Hence,9+1 = 10 flip-flops are required to count from 0 to 512.