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Question

To determine the diameter of a rod a student wound a thread 5times around the rod and measured the length of thread as 156mmon a meter scale. Using this value he calculated the diameter of the rod. If the actual diameter of the rod is 9.94mmwhat is the error that could result in the method followed by the student?Takeπ=227


A

+0.01mm

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B

0.01mm

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C

+0.02mm

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D

0.02mm

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Solution

The correct option is B

-0.01mm


Step 1: Given data:

Actual Diameter of rod = 9.94 mm

Length of thread = 156 mm

The student wound the thread 5timesaround the rod.

which is equal to 5circumference of the rod.

Step 2: Formula

circumference=πD

5x(circumference)=156mm5πDmeasured=156mm

Dm=156×75×22=9.93mm

Hence the diameter of the rod found by the thread method is 9.93 mm.

Actualdiameter=9.94mm

Eorror=(Dactual-Dmeasured)=9.94-9.93=0.01mm

since the measured value is less than actual

error=-0.01mm .

The correct option is B.


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