What is the value of $x$ , if $\sin 2 x = (\sin 60 ° \cos 30 °) - (\cos 60 ° \sin 60 °) ?$

Open in App

Solution

Let's find the value of $x$
To determine the value of $x$ , the below formula is used: $\sin (A - B) = \sin A . \cos B - \cos A . \sin B$
Substituting the values of $A$ and $B$ where $A = 60 °$ , $B = 30 °$
$\begin{array}{rcl} 2 x & = & (60 - 30) \\ = & 30 \\ x & = & 15 \end{array}$
Hence, the value of $x = 15$

Suggest Corrections

Similar questions

sin (60^{\circ} + 30^{\circ})

sin 60^{\circ} cos 30^{\circ} + sin 30^{\circ} cos 60^{\circ}

sin (60^{\circ} + 30^{\circ}) .

x

sin 2 x = sin 60^{\circ} cos 30^{\circ} - cos 60^{\circ} sin 30^{\circ}

x

cos 2 x = cos 60^{o} cos 30^{o} + sin 60^{o} sin 30^{o}

cos 2 x = cos 60^{\circ} cos 30^{\circ} + sin 60^{\circ} sin 30^{\circ}

Join BYJU'S Learning Program