Question

To determine the Young's modulus of a wire, the formula is $Y=\frac{F}{A}\times$$\frac{L}{\Delta L}$where L= length, $A=$ area of cross-section of the wire, $\Delta L=$ change in length of the wire when stretched with a force $F$. The conversion factor to change it from CGS to MKS system is

• A. $10$
• B. $0.01$
• C. $0.1$
• D. $1$

Answer 1

The correct option is C $0.1$

As we know,
The unit of force in SI system is Newton and in CGS unit is dyne.
$1N={10}^5$ dyne
$1m=100cm$
According to the given condition
$Y=\frac{F}{A}.\frac{L}{\Delta L}=\frac{\text{dyne}}{c{m}^2}=\frac{{10}^{-}5N}{{10}^{-}4m^2}$
$0.1$ $N/m^2$