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Question

To divide a line segment AB in the ratio 3: 4 we draw a ray AX, so that angle BAX is an acute angle, and then mark the points on the ray AX at equal distances such that the minimum number of these points is

A
3
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B
4
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C
7
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D
12
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Solution

The correct option is B 7
The line is to be divided in 3:4
Let the parts be 3x and 4x
3x=x+x+x
So 3x has 3 equal parts
Similarly 4x=x+x+x+x
So 4x has four equal parts.
So a total of 7 points are needed.
Option C is correct.

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