Question

To divide a line segment AB in the ratio 3: 4 we draw a ray AX, so that angle BAX is an acute angle, and then mark the points on the ray AX at equal distances such that the minimum number of these points is

• A. 3
• B. 4
• C. 7
• D. 12

Answer 1

Answer: (C)

7

The line is to be divided in $3:4$

Let the parts be $3x$ and $4x$

$3x=x+x+x$

So $3x$ has $3$ equal parts

Similarly $4x=x+x+x+x$

So $4x$ has four equal parts.

So a total of $7$ points are needed.

Option $C$ is correct.