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Question 1
To divide a line segment AB in the ratio 5:7 first a ray AX is drawn so that
BAX is an acute angle and then at equal distances points are marked on the ray AX such that the minimum number of these points is
(A) 8
(B) 10
(C) 11
(D) 12​​​​​​​

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Solution

We know that, to divide a line segment AB in the ratio m,n, first draw a ray AX which makes an acute angle BAX, the marked m+n points at equal distance.
Here, m=5, n=7.
So, minimum number of these points = m+n = 5+7=12.


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