Locus of the Points Equidistant From Two Given Points
Question 1 To...
Question
Question 1 To divide a line segment AB in the ratio 5:7 first a ray AX is drawn so that ∠BAX is an acute angle and then at equal distances points are marked on the ray AX such that the minimum number of these points is (A) 8 (B) 10 (C) 11 (D) 12
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Solution
We know that, to divide a line segment AB in the ratio m,n, first draw a ray AX which makes an acute angle ∠BAX, the marked m+n points at equal distance. Here, m=5, n=7. So, minimum number of these points = m+n = 5+7=12.