Question

Question 1
To divide a line segment AB in the ratio 5:7 first a ray AX is drawn so that $\angle$BAX is an acute angle and then at equal distances points are marked on the ray AX such that the minimum number of these points is
(A) 8
(B) 10
(C) 11
(D) 12​​​​​​​

Answer 1

We know that, to divide a line segment AB in the ratio m,n, first draw a ray AX which makes an acute angle $\angle$BAX, the marked m+n points at equal distance.
Here, m=5, n=7.
So, minimum number of these points = m+n = 5+7=12.