To divide a line segment $A B$ in the ratio $5 : 7$ , first a ray $A X$ is drawn so that $B A X$ is an acute angle and then at equal distances points are marked on the ray $A X$ such that the minimum number of these points is

$8$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$10$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$11$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$12$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D
$12$

Let's find the minimum number of points.
According to the given details, we know that
A line segment $A B$ in the ratio $5 : 7$
So, $A : B = 5 : 7$
Draw a ray $A X$ making an acute angle $∠ B A X$ ,
Mark $A + B$ points at equal distance.
So, we have $A = 5$ and $B = 7$
Hence, minimum number of these points $A + B = 5 + 7 = 12$

Suggest Corrections

Similar questions

Q. To divide a line segment AB in the ratio 5:7, first ray AX is drawn so that ∠BAX is an acute angle and then at equal distances points are marked on the ray AX such that the minimum number of these points is
(a) 8
(b) 10
(c) 11
(d) 12

Q. To divide a line segment

A B

internally in the ratio

5 : 7

, first a ray

A X

is drawn so that

∠ B A X

is an acute angle and then at equal distances points are marked on ray

A X

such that the minimum number of these points is

To divide a line segment $A B$ in the ratio $5 : 7$ , first a ray $A X$ is drawn so that $∠ B A X$ is an acute angle and then at equal distances points are marked on the ray $A X$ such that the minimum number of these points is:

Q. To divide a line segment AB in the ratio 5:7, first a ray AX is drawn so that

∠

BAX is an acute angle and then at equal distances points are marked on the ray AX such that the minimum number of these points is:

Q. To divide a line segment

A B

internally in the ratio

3 : 5

, first a ray

A X

is drawn so that

B A X

is an acute angle and then at equal distances points are marked on the ray

A X

such that the minimum number of these points is :

Join BYJU'S Learning Program

To divide a line segment ABin the ratio 5:7, first a ray AX is drawn so that BAXis an acute angle and then at equal distances points are marked on the ray AX such that the minimum number of these points is

To divide a line segment $A B$ in the ratio $5 : 7$ , first a ray $A X$ is drawn so that $B A X$ is an acute angle and then at equal distances points are marked on the ray $A X$ such that the minimum number of these points is