Question

To divide a line segment $PQ$ in $3$ equal points, a ray $PX$ is drawn such that $\angle QPX$ is acute and then at equal distances points are marked on ray $PX$. The minimum number of points required is:

• A. $2$
• B. $3$
• C. $4$
• D. $5$

Answer 1

Answer: (B)

$3$

For dividing $PQ$ into three equal parts, we need two points $R$ and $S$ such that $PR=RS=SQ$.

Hence, we need $3$ equidistant points on ray $PX$ which could then be projected on line $PQ$ to obtain $R$ and $S$.