Question

To divide the line segment AB in the ratio of 2 : 3, first a ray AX is drawn such that angle BAX is an acute angle and then at equal distance, points are marked on the ray AX such that the minimum number of these points is :

• A. 5
• B. 3
• C. 2
• D. 6

Answer 1

Answer: (A)

5

The line is to be divided in $2:3$

Let the parts of line be $2x$ and $3x$

$2x=x+x$

So $2x$ has $2$ equal parts.

$3x=x+x+x$

So $3x$ has $3$ equal parts.

So a total of $5$ equal parts are needed.