To draw a histogram to represent the foll wing frequency distribution:
Class interval 5-10 10-15 15-25 25-45 45-75
Frequency 6 12 10 8 15

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Solution

$\Rightarrow$ Adjusted frequency $= \frac{f}{W i d t h o f t h e c l a s s} \times 5$
$C . I$ $f$ $W i d t h o f t h e c l a s s$ $A d j u s t e d f r e q u e n c y$
$5 - 10$ $6$ $5$ $\frac{6}{5} \times 5 = 6$
$10 - 15$ $12$ $5$ $\frac{12}{5} \times = 12$
$15 - 25$ $10$ $10$ $\frac{10}{10} \times 5 = 5$
$25 - 45$ $8$ $20$ $\frac{8}{20} \times 5 = 2$
$45 - 75$ $15$ $30$ $\frac{15}{30} \times 5 = 2.5$

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Similar questions

Q. Consider the following frequency distribution:

Class interval :	5 – 10	10 – 15	15 – 25	25 – 45	45 – 75
Frequency :	6	12	10	8	15

To draw a histogram to represent the above frequency distribution the adjusted frequency for the class 25-45 is
(a) 6
(b) 5
(c) 3
(d) 2

Question 10
To draw a histogram to represent the frequency distribution.
$\begin{matrix} Class interval & 5 - 10 & 10 - 15 & 15 - 25 & 25 - 45 & 45 - 75 Frequency & 6 & 12 & 10 & 8 & 15 \end{matrix}$
The adjusted frequency for the class 25 - 45 is:

A) 6
B) 5
C) 3
D) 2

Q. Mean for the following frequency distribution table.

0-5	5-10	10-15	15-20	20-25	25-30
5	3	9	10	8	5

Q. The frequency distribution of marks obtained by students in a class test is given below:

Marks	:	0-10	10-20	20-30	30-40	40-50
No. of Students	:	3	10	14	10	3

Draw a histogram to represent the frequency distribution of marks . Comment on the shape of the histogram.

Q. Find the mode of the following distribution.
(i)

Class-interval:	0-10	10-20	20-30	30-40	40-50	50-60	60-70	70-80
Frequency:	$5$	$8$	$7$	$12$	$28$	$20$	$10$	$10$

(ii)

Class-interval:	10-15	15-20	20-25	25-30	30-35	35-40
Frequency:	$30$	$45$	$75$	$35$	$25$	$15$

(iii)

Class-interval:	25-30	30-35	35-40	40-45	45-50	50-60
Frequency:	$25$	$34$	$50$	$42$	$38$	$14$

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$C . I$	$f$	$W i d t h o f t h e c l a s s$	$A d j u s t e d f r e q u e n c y$
$5 - 10$	$6$	$5$	$\frac{6}{5} \times 5 = 6$
$10 - 15$	$12$	$5$	$\frac{12}{5} \times = 12$
$15 - 25$	$10$	$10$	$\frac{10}{10} \times 5 = 5$
$25 - 45$	$8$	$20$	$\frac{8}{20} \times 5 = 2$
$45 - 75$	$15$	$30$	$\frac{15}{30} \times 5 = 2.5$

To draw a histogram to represent the foll wing frequency distribution:Class interval5-1010-1515-2525-4545-75Frequency 61210815

⇒ Adjusted frequency =fWidthoftheclass×5C.I f WidthoftheclassAdjustedfrequency 5−10 6 5 65×5=6 10−15 12 5 125×=12 15−25 10 10 1010×5=5 25−45 8 20 820×5=2 45−75 15 30 1530×5=2.5

To draw a histogram to represent the foll wing frequency distribution:
Class interval 5-10 10-15 15-25 25-45 45-75
Frequency 6 12 10 8 15