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Question

To draw a histogram to represent the foll wing frequency distribution:
Class interval5-1010-1515-2525-4545-75
Frequency 61210815

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Solution


Adjusted frequency =fWidthoftheclass×5
C.I f WidthoftheclassAdjustedfrequency
510 6 5 65×5=6
1015 12 5 125×=12
1525 10 10 1010×5=5
2545 8 20 820×5=2
4575 15 30 1530×5=2.5

1212046_1038318_ans_d1c1d2c2aefe4aa5857556ea745bd19e.png

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