To draw a pair of tangents to a circle, which are inclined to each other at an angle of 45^o, we have to draw tangents at the end points of those two radii, the angle between which is
(a) 105o (a) 135o (a) 140o (a) 145o
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Solution
OA and OB are two redii on tangent SO <OAP=90° and <OBP=90°
<APB=45° (GIVEN)
So in quadratic APBO <OAP+<APB+<OBP+<AOB=360° 90°+45°+90°+<AOB=360° <AOB=360°-225°=135°