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Standard VIII

Mathematics

Construction of a Square When a Diagonal Is Given.

To draw a per...

Question

To draw a perpendicular line through a point "P" not on the line. The fist step is draw the arcs centered at P and intersects the line at Q and R. If the perpendicular distance between line and point is $7$ units. What could be the lengths of PQ and PR?

PQ = PR = 7 units

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PQ = 7 units and PR = 9 units

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PQ = PR > 7

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PQ = PR < 7

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Solution

The correct option is C $PQ = PR > 7$
As we know, Perpendicular distance (shortest distance) between point P and line is $7$ units. Arcs radii must be greater than $7$ units, so that arcs could interseect the line at two distinct points.

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To draw a perpendicular line through a point "P" not on the line. The fist step is draw the arcs centered at P and intersects the line at Q and R. If the perpendicular distance between line and point is 7 units. What could be the lengths of PQ and PR?

The correct option is C PQ = PR>7As we know, Perpendicular distance (shortest distance) between point P and line is 7 units. Arcs radii must be greater than 7 units, so that arcs could interseect the line at two distinct points.

To draw a perpendicular line through a point "P" not on the line. The fist step is draw the arcs centered at P and intersects the line at Q and R. If the perpendicular distance between line and point is $7$ units. What could be the lengths of PQ and PR?

The correct option is C $PQ = PR > 7$
As we know, Perpendicular distance (shortest distance) between point P and line is $7$ units. Arcs radii must be greater than $7$ units, so that arcs could interseect the line at two distinct points.