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Byju's Answer
Standard XII
Mathematics
Integration by Substitution
To evaluate ...
Question
To evaluate
∫
d
x
(
x
−
1
)
√
−
x
2
+
3
x
−
2
one of the most suitable substitution could be
A
√
−
x
2
+
3
x
−
2
=
u
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B
√
−
x
2
+
3
x
−
2
=
(
u
x
√
2
)
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C
√
−
x
2
+
3
x
−
2
=
u
(
1
−
x
)
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D
√
−
x
2
+
3
x
−
2
=
u
(
x
−
2
)
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Solution
The correct options are
C
√
−
x
2
+
3
x
−
2
=
u
(
1
−
x
)
D
√
−
x
2
+
3
x
−
2
=
u
(
x
−
2
)
−
x
2
+
3
x
−
2
=
−
x
2
+
2
x
+
x
−
2
=
−
x
(
x
−
2
)
+
1
(
x
−
2
)
=
(
1
−
x
)
(
x
−
2
)
has real roots
1
and
2
So from case III:
√
−
x
2
+
3
x
−
2
=
u
(
1
−
x
)
or
u
(
x
−
2
)
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Similar questions
Q.
If
∫
d
x
√
x
2
−
3
x
+
2
=
log
(
A
|
+
C
,
then
A
=
.