To expel half the mass of air from a large flask at 27∘C, it must be heated to
54°C
177°C
277°C
327°C
PV = nRT
at cosntant t P and V
n1T1 = n2T2
n1 × 300 = n12 × T
∴ T = 600K = 327∘ C
An open flask contains air at 27∘ C. To what temperature it must be heated to expel one-fourth of the volume?
The temperature at which the speed of sound in air becomes double of its value at 27∘ C is