To fill 12 vacancies there are 25 candidates of which five are from scheduled caste. If 3 of the vacancies are reserved for scheduled caste candidates while the rest are open to all, then the number of ways in which the selection can be made __________.

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Solution

The correct option is A

Since 3 vacancies filled from 5 candidates in $^{5} C_{3}$ ways and now remaining candidates are 22 and remaining seats are 9.

By multiplication rule,

The selection can be made in $^{5} C_{3} \times^{22} C_{9}$

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To fill 12 vacancies there are 25 candidates of which five are from scheduled caste. If 3 of the vacancies are reserved for scheduled caste candidates while the rest are open to all, then the number of ways in which the selection can be made __________.

The correct option is A Since 3 vacancies filled from 5 candidates in 5C3 ways and now remaining candidates are 22 and remaining seats are 9. By multiplication rule, The selection can be made in 5C3×22C9

The correct option is A

Since 3 vacancies filled from 5 candidates in $^{5} C_{3}$ ways and now remaining candidates are 22 and remaining seats are 9.

By multiplication rule,

The selection can be made in $^{5} C_{3} \times^{22} C_{9}$