To find the conversion factor b/w the units of force-
i.e newton in si system to dyne is cgs system-
in x dyne
dimension of force are [L1M1T−2]
[L11M11T1−2]=X[L21M21T2−2]
X=(L1L2)+1(M1M2)+1(T1T2)−2
WHERE suffix I indicates si system and suffix 2 indicates c.g.s – system
In S.I. system L,M and T are expressed in m, kg,scgs system, L,M and T are expressed in m,g,s
x=(mm)1(kgg)1(ss)−2
=(102)(103)(1)−2
x=105
1N=105dyne