To find the length of a ladder making an angle - with wall - trigonometric ratio is used-

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To find the l...

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To find the length of a ladder making an angle $θ$ with wall ................. trigonometric ratio is used.

t a n θ

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c o t θ

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c o s e c θ

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θ

x

θ

\sin A = \frac{2}{3}

\cos A = \frac{4}{5}

\sin θ = \frac{11}{15}

\tan α = \frac{5}{12}

\sin θ = \frac{\sqrt{3}}{2}

\cos θ = \frac{7}{25}

\tan θ = \frac{8}{15}

\cot θ = \frac{12}{5}

\sec θ = \frac{13}{5}

cosec θ = \sqrt{10}

\cos θ = \frac{12}{15}

Some trigonometric ratios and the interval in which $θ$ lies is given. Match the intervals with the ratios which are positive in those intervals.

$θ$ gives positive values

p. (0, $\frac{π}{2}$ ) 1. Only sin $θ$ , cosec $θ$

q. ( $\frac{π}{2}$ , $π$ ) 2. Only cos $θ$ , sec $θ$

r. $(π, \frac{3 π}{2})$ 3. Only tan $θ$ , cot $θ$

s. $(\frac{3 π}{2}, 2 π)$ 4. All sin $θ$ , cos $θ$ , tan $θ$ , cot $θ$ , sec $θ$ , cosec $θ$

60^{\circ}

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