Question

To form a composite $16\mu F,1000V$ capacitor from a supply of identical capacitors marked $8\mu F,250V,$ we require a minimum number of $n$ capacitors where $n$ is :-

• A. $40$
• B. $32$
• C. $8$
• D. $2$

Answer 1

The correct option is B $32$

REF. Image.

Let n series conncher of 8 mf are conduct and there are joined m times in parallel.

we need to get $V_{new}=1000V$

$=V_{new}=n\times V_{oil}$

$\therefore n=\frac{1000}{250}=4$

$Ceq=16MF=\left(\frac{C}{n}\right)\to F.series\times M$ for parallel.

$16=\frac{m}{4}$

$m=8$

$\therefore$ Total carbona for repl

$=m\times n=32$