Question

To get a resultant displacement of $10cm$, two displacement vectors, one of magnitude $6cm$ and another of $8cm$, should be combined:

• A. at an angle ${60}^{\circ }$
• B. perpendicular to each
• C. parallel
• D. anti-parallel

Answer 1

The correct option is B perpendicular to each

Let $\theta$ be the angle between the two displacement vectors, then
${10}^2=6^2+8^2+2\times 6\times 8\cos \theta$
$2\times 6\times 8\cos \theta =0$
$\cos \theta =0$
$\theta =\frac{\pi }{2}$