Question

To get maximum current in a resistance of $3\Omega$, one can use n rows of m cells (connected in series) connected in parallel. If the total number of cells is 24 and the internal resistance of a cell is $0.5\Omega$, then

• A. $m=12,n=2$
• B. $n=3,m=8$
• C. $m=2,n=12$
• D. $m=6,n=4$

Answer 1

Answer: (A)

$m=12,n=2$

As we know for getting maximum current through output resistor we should have resultant internal resistance equals to output external resistance.

therefore,

$\frac{mr}{n}=R\frac{m\times 0.5}{n}=3\frac{m}{n}=6$ also $m\times n=24$

$⟹m=12:n=2$