To get the terminating decimal expansion of a rational number pq- if q - 2m 5n then m and n must belong to -

If $\frac{p}{q}$ is a rational number with terminating decimal expansion where $p$ and $q$ are coprimes, then $q$ can be represented as:
(Here, n and m are non-negative integers.)

Let $x = \frac{p}{q}$ be a rational number, such that the prime factorisation of $q$ is not of the form $2^{m} 5^{n}$ , where $n, m$ are non-negative integers. Then, $x$ has a decimal expansion which is

Q. If

x = \frac{p}{q}

be a rational number such that the prime factorization of

q

is not of the form

2^{n} 5^{m}

, where

n, m

are non-negative integers. Then

x

has a decimal expansion which is terminating.

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To get the terminating decimal expansion of a rational number pq. if q=2m5n then m and n must belong to .................

The correct option is C NTo get the terminating decimal expansion of a rational number pq, q have to be an integer or natural number.Now, q=2m5n will be an integer or natural if m and n both are naturals. So, to get q=2m5n as integer m and n must belong to N.Hence, option C is correct.

To get the terminating decimal expansion of a rational number $\frac{p}{q}$ . if $q = 2^{m} 5^{n}$ then $m$ and $n$ must belong to .................