To get _________ triplets we use the general form $2 m, m^{2} + 1, m^{2} - 1$ .

Square number

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Consecutive number

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Repeated

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Pythagorean

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Solution

The correct option is C Pythagorean
$2 m, m^{2} + 1, m^{2} - 1$ forms are used to get Pythagorean Triplets.

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Similar questions

, $m^{2} + 1, m^{2} - 1 f o r m a P y t h a g o r e a n t r i p l e t$

(m^{2} - 1), (2 m), m^{2} + 1

Question 10

Write the correct answer from the given four options.

If one member of a Pythagorean triplet is $2 m$ , then the other two members are

a) $m, m^{2} + 1$
b) $m^{2} + 1, m^{2} - 1$
c) $m^{2}, m^{2} - 1$
d) $m^{2}, m + 1$

Evaluate: $(2 m^{3} + m^{2} + m + 9) \div (2 m - 1)$

2 m - \frac{1}{2 m} = 2

m^{2} + \frac{1}{16 m^{2}}

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