To have a steep slide at a height of 6 m, and inclined at an angle of $60^{\circ}$ to the ground. What should be the length of the slide (in m)?

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Solution

The correct option is C
4

The above figure represents the given situation.
In the given right-agled triangle,
$s i n (∠ A C B) = \frac{A B}{A C} \Rightarrow s i n 60^{\circ} = \frac{6 m}{A C} \Rightarrow A C = \frac{6}{\frac{\sqrt{3}}{2}} = \frac{12}{\sqrt{3}} = 4 \sqrt{3} m ∴ l e n g t h o f s l i d e = 4 \sqrt{3} m$

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A contractor plans to install two slides for the children to play in a park for elder children. She wants to have a steep slide at a height of 6 m and inclined at an angle of $60^{\circ}$ to the ground. What should be the length of the slide (in m)?

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To have a steep slide at a height of 6 m, and inclined at an angle of 60∘ to the ground. What should be the length of the slide (in m)?

The correct option is C 4 The above figure represents the given situation. In the given right-agled triangle, sin(∠ACB)=ABAC⇒sin60∘=6mAC⇒AC=6√32=12√3=4√3 m∴length of slide=4√3 m

To have a steep slide at a height of 6 m, and inclined at an angle of $60^{\circ}$ to the ground. What should be the length of the slide (in m)?