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Standard XII

Chemistry

pH the Power of H

To have more ...

Question

To have more sulphide ion concentration, $H_{2} S$ should be passed through:

1 N H C l

solution

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0.1 M H C l

solution

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A neutral solution such as water

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An ammonical solution

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Solution

The correct option is D $1 N H C l$ solution
To have more concentration of sulphide ion, $H_{2} S$ should be passed to acidic solution with higher concentration. Hence in $H C l$ solution is used.

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Similar questions

Q. Assertion :

S b (I I I)

is not precipitated as sulphide when in its alkaline solution

H_{2} S

is passed. Reason: Concentration of

S^{2 -}

ions in alkaline medium is inadequate for precipitation.

Q. Assertion :When

H_{2} S

gas is passed into an aqueous solution of

Z n C l_{2}, Z n^{2 +}

ions are completely precipitated as zinc sulphide. Reason: Zinc sulphide is insoluble in solutions of caustic alkali but dissolves in dilute

H C I

Q. Upon treatment with ammonical

H_{2} S

, the metal ion that precipitates as a sulphide is:

Q. Aqueous solution contains

Z n {(C H_{3} C O O)}_{2}

C d {(C H_{3} C O O)}_{2}

, and

C u {(C H_{3} C O O)}_{2}

. On passing

H_{2} S

gas, there is a precipitation of ______ as sulphide

The concentration of sulphide ion in 0.1M HCl solution saturated with hydrogen sulphide is 1.0 × 10^–19 M. If 10 mL of this is added to 5 mL of 0.04 M solution of the following: FeSO₄, MnCl₂, ZnCl₂ and CdCl₂. in which of these solutions precipitation will take place?

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To have more sulphide ion concentration, H2S should be passed through:

The correct option is D 1 N HCl solutionTo have more concentration of sulphide ion, H2S should be passed to acidic solution with higher concentration. Hence in HCl solution is used.

To have more sulphide ion concentration, $H_{2} S$ should be passed through:

The correct option is D $1 N H C l$ solution
To have more concentration of sulphide ion, $H_{2} S$ should be passed to acidic solution with higher concentration. Hence in $H C l$ solution is used.