Question

To increase the length of brass rod by 2% its temperature should increase by:$(\propto =0.00002K^{-1})$

• A. $800$
• B. $900$
• C. $1000$
• D. $1100$

Answer 1

Answer: (C)

$1000$

$\frac{\Delta L}{L}=2$%$=\frac{2}{100}$

$\propto =0.00002K^{-1}$

As $\Delta L=\propto L\Delta T$

or $\Delta T=\frac{\Delta L}{\propto L}=\frac{2}{100\times 0.00002}=\frac{1}{0.001}$

$={10}^3=1000$