To know that the oxidation state of cr2 o7 (6) is reduced to 3 do we need to byheart the following reaction??Cr2O72- + 6Fe2+ + 14H+ ----> 2Cr3+ + 6Fe3+ + 7H2O

Open in App

Solution

Dear Student

Yes, its essential to learn the equations, especially dichromate ions equation is an important one.

Regards

Suggest Corrections

Similar questions

Write half-reactions using electrons.

{C r}_{2} O_{2}^{7 -} + 6 {F e}^{2 +} + 14 H^{+} ⟶ 2 {C r}^{3 +} + 6 {F e}^{3 +} + 7 H_{2} O

Q. Given a reaction:

{C r}_{2} O_{7}^{2 -} + {F e}^{2 +} + H^{\oplus} ⟶ {C r}^{3 +} + {F e}^{3 +} + H_{2} O

The balanced equation is

6 {F e}^{2 +} + 14 H^{\oplus} + {C r}_{2} O_{7}^{2 -} ⟶ 6 {F e}^{3 +} + 2 {C r}^{3 +} + 7 H_{2} O

.
If true enter 1, else enter 0.

Q. The cell reaction

{C r}_{2} O_{7}^{2 +} (a q) + 14 H^{+} (a q) + 6 {F e}^{2 +} (a q) \to 6 {F e}^{3 +} (a q) + 2 {C r}^{3 +} (a q) + 7 H_{2} O (l)

, is best represented by:

Q. The standard reaction, Gibbs energy for the electrochemical reaction.

C r_{2} O_{7}^{2 -} + 6 F e^{2 +} + 14 H^{+} \to 2 C r^{3 +} + 6 F e^{3 +} + 7 H_{2} O i s - 793 k J m o l^{- 1}

The standard cell potential is:

How many $H_{2} O$ should be added to the RHS of the following equation to balance number of oxygen atoms on the left ?

$6 F e^{2 +} + C r_{2} O_{7}^{2 -} + 14 H^{+} ⟶ 6 F e^{3 +} + 2 C r^{3 +} +$ ___________

Join BYJU'S Learning Program

To know that the oxidation state of cr2 o7 (6) is reduced to 3 do we need to byheart the following reaction??Cr2O72- + 6Fe2+ + 14H+ ----> 2Cr3+ + 6Fe3+ + 7H2O

Dear Student Yes, its essential to learn the equations, especially dichromate ions equation is an important one. Regards

Dear Student

Yes, its essential to learn the equations, especially dichromate ions equation is an important one.

Regards