Question

To lift an automobile of $1600kg$, a hydraulic pump with a larger piston $800c{m}^2$ in area is employed. If the area of the smaller piston is $10c{m}^2$. The force that must be applied on it is

• A. $20N$
• B. $20kgf$
• C. $200kgf$
• D. $200N$

Answer 1

The correct option is C $200kgf$

The pressure in hydraulic pump is same at both pistons,

Force required to lift 1600kg body = 16000 N

Now,

$\frac{f_1}{a_1}=\frac{f_2}{a_2}\to \frac{16000}{800}=\frac{f_2}{10}whichgives{f}_2=200N=200kgf$