wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

To lift an automobile of 5000 kg, a hydraulic lift with a large piston 800 cm2 in area is employed. Calculate the force that must be applied to a small piston of area 5 cm2 to achieve it.

A
612.5 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
306.25 N
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
153.12 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
408.56 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 306.25 N
Force on large pistion (F1)=mg
F1=5000×9.8 N=4.9×104 N
Given area of large piston, A1=800 cm2
Pressure on the large pistion (P)= F1A1=4.9×104800×104=6.125×105 Pa
Since the liquid transmits pressure equally, therefore the pressure on the small piston will be equal to the pressure on the large pistion.
F1A1=F2A2=P
Given area of small pistion A2=5 cm2
Force applied on small pistion(F2)=P×A2
=6.125×105×(5×104)=306.25 N

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon