Question

To neutralize $40.0mL$ of a $0.1MHCl\left(aq\right)$, the volume of $0.2MNaOH\left(aq\right)$ required is :

• A. $10.0mL$
• B. $40.0mL$
• C. $80.0mL$
• D. $20.0mL$
• E. $100.0mL$

Answer 1

Answer: (D)

$20.0mL$

$HCl$ is a monobasic acid while $NaOH$ is a monoacidic base.

The reaction would be:

$HCl+NaOH\to NaCl+H_{2}O$

Thus same moles of $HCl$ and $NaOH$ will react to neutralize each other.

$M_1{V}_1=M_2{V}_2$

$V_2=\frac{0.1M\times 40.0mL}{0.2M}=20mL$