To obtain a given range of a projectile, there are two possible angles of projection with the horizontal. If R is the range for an angle of projection of 25o, then the other possible angle of projection is
A
20o
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B
65o
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C
70o
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D
90o
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Solution
The correct option is B65o The given range is same for two complementary angles ie rang is same for θ1 and θ2 if θ1+θ2=90o Given, θ1=25o ∴25o+θ2=90o ⇒θ2=90o−25o=65o