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Percentage Composition

To prepare ...

Question

To prepare $100$ g of a $92$ % by weight solution of $N a O H$ , how many grams of $H_{2} O$ is needed?

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Solution

Weight of $N a O H = (\frac{92 g}{100 g s o l u t i o n})$ $(100 g s o l u t i o n)$ $= 92 g N a O H$
Weight of $H_{2} O = 100 - 92 = 8.0 g H_{2} O$

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