Question

To prepare $100$ g of a $92$% by weight solution of $NaOH$, how many grams of $H_{2}O$ is needed?

Answer 1

Weight of $NaOH=\left(\frac{92g}{100gsolution}\right)$$\left(100gsolution\right)$ $=92gNaOH$
Weight of $H_{2}O=100-92=8.0g{H}_{2}O$