To prepare a pure sample of n-hexane using sodium metal as one reactant, the other reactant or reactants will be:

Ethyl Chloride and N-Butyl Chloride

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Methyl Bromide and N-Pentyl Bromide

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n-propyl bromide

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Ethyl Bromide and N-Butyl Bromide

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Solution

The correct option is C n-propyl bromide
$2 C H_{3} C H_{2} C H_{2} B r n - p r o p y l (b r o m i d e) + 2 N a E t h e r ⟶ C H_{3} - C H_{2} - C H_{2} - C H_{2} - C H_{2} - C H_{3} + 2 N a B r n - H e x a n e$

$T h i s i s W u r t z r e a c t i o n .$

The reaction forms R-R' , so it is possible to use Options 1 and 2 to form hexane.
But those 2 can also form a number of other products, which is not feasible.

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