The correct option is A n-propyl bromide
According to wurtz reaction, the alkyl groups in the alkyl halides will combine to form an alkane. In this case however, we have multiple possible options.
But remember that if you use propyl halides, only hexane will be produced. Other alkyl halides will cause unwanted dimer products. For example, ethyl halide with butyl halide will give 3 products- Butane, Hexane and Octane.
The reaction can be summarised as:
2CH3CH2CH2Br+2Naether−−−→CH3(CH2)4CH3+2NaBr