To prepare hydrogen sulfide the proportion of paraffin wax and sulfur should be

2:1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3:1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1:2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1:4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 2:1
Two parts of paraffin wax and one part of sulfur are mixed and heated above 160 C. During the reaction hydrogen sulfide is produced. The speed of reaction is proportional to the temperature.
Hence option A is correct.

Suggest Corrections

Similar questions

H_{2} (g) + S (s) ⇌ H_{2} S (g)

Substance	$k_{a}$
Hydrogen carbonate ion (bicarbonate ion) $H C O_{3}^{-}$	$4.8 \times 10^{- 11}$
Hydrogen phosphate ion $H P O_{4}^{- 3}$	$3.6 \times 10^{- 13}$
Water $H_{2} O$	$1.0 \times 10^{- 14}$
Hydrogen sulfide ion $H S^{-}$	$1.0 \times 10^{- 19}$

Join BYJU'S Learning Program