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Question

To prepare XeF6 at 573 K, 60-70 atm pressure, the ratio of xenon and fluorine used is :

A
1 : 2
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B
1 : 5
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C
1 : 20
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D
10 : 1
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Solution

The correct option is C 1 : 20
The ratio of xenon and fluorine is 1:20 at 573 K, 50-60 atm pressure to prepare XeF6.

Xe(g)+3F2(g)573K,6070 bar−−−−−−−−XeF6(s)
(1:20 ratio)

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