To prove $(a + b) (a - b) = a^{2} - b^{2}$

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Solution

$(a + b) (a - b) = a (a - b) + b (a - b) = a^{2} - a b + a b - b^{2}$
= $(a + b) (a - b) = a^{2} - b^{2}$

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Similar questions

\frac{\sqrt{a^{2} - b^{2}} + a}{\sqrt{a^{2} + b^{2}} + b} \div \frac{\sqrt{a^{2} + b^{2}} - b}{a - \sqrt{a^{2} - b^{2}}} = \frac{b^{2}}{d^{2}}

a^{2} - b^{2} = (a - b) (a + b)

What is the value of $(a + b) (a - b) ?$

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