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Effective Equilibrium Constant

To significan...

Question

To significantly increase the concentration of free $Z n^{2 +}$ ion in a solution, we should add _______ for the given equilibrium.
$Z n^{2 +} (a q) + 4 N H_{3} (a q) ⇌ [Z n (N H_{3})_{4}]^{2 +} (a q)$

H_{2} O (a q)

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H C l (a q)

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N H_{3} (a q)

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N H_{4} C l (a q)

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Solution

The correct option is B $H C l (a q)$
On adding $H C l$ , the equilibrium will shift in the backward direction thus increasing the concentration of free $Z n^{2 +}$ ion in the solution.

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Similar questions

Z n^{2 +}

{[Z n {(N H_{3})}_{4}]}^{2 +}

{Z n^{2 +}}_{(a q)} + 4 N H_{3} ⇌ {[Z n {(N H_{3})}_{4}]}^{2 +}_{(a q)}

N H_{3} (g) + H C l (g) \to N H_{4} C l (s)

N H_{3} (g) + a q \to N H_{3} (a q),

Δ H = - 8.4 K . C a l .

H C l (g) + a q \to H C l (a q),

Δ H = - 17.3 K . C a l .

N H_{3} (a q) + H C l (a q) \to N H_{4} C l (a q), Δ H = - 12.5 K . C a l s .

N H_{4} C l (s) + a q \to N H_{4} C l (a q), Δ H = + 3.9 K . C a l .

298

Z n^{2 +} + 4 N H_{3} ⇌ [Z n (N H_{3})_{4}]^{2 +}

10^{9}

E_{[Z n (N H_{3})_{4}]^{2 +} / [Z n^{2 +} + 4 N H_{3}]}^{o} = - 1.03

E_{Z n / Z n^{2 +}}^{o}

298 K

Z n (s) | Z n^{2 +} (a q, C_{1}) | | Z n^{2 +} (a q, C_{2}) | Z n (s)

C_{1} & C_{2} are concentrations of Z n^{2 +} ions of each half-cell.

298 K

Z n (s) | Z n^{2 +} (a q, C_{1}) | | Z n^{2 +} (a q, C_{2}) | Z n (s)

C_{1} & C_{2} are concentrations of Z n^{2 +} ions of each half-cell.

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