To the captain of a ship 𝐴 travelling with velocity →A=(3^i−4^j)km/hr , a second ship B appears to have a velocity (5^i+12^j)km/hr. What is the true velocity of the ship B ?
A
(−2^i−16^j)km/hr
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B
8(^i+^j)km/hr
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C
(13^i+8^j)km/hr
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D
(2^i+16^j)km/hr
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Solution
The correct option is B8(^i+^j)km/hr Given, →VA=(3^i−4^j)km/hr →VBA=(5^i+12^j)km/hr
True velocity of B: →VB=→VA+→VBA =3^i−4^j+5^i+12^j =(8^i+8^j)km/hr
Final Answer: (d)