To the Daniel cell $C u S O$ $_{4}$ is added to the left-hand side electrode. Then cell $E M F$ :

increases

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decreases

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does not change

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first increases & then decreses

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Solution

The correct option is B decreases
In Daniel cell, the left hand side electrode is zinc immersed in zinc sulphate. When copper sulphate solution is added to this, the molarity of zinc sulphate solution decreases. Therefore, the oxidation potential of this electrode decreases. Hence the emf of cell decreases.
Hence, option B is correct.

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Similar questions

Z n S O_{4}

C u S O_{4}

E M F

1.083 v o l t

- 0.018 v o l t

25^{\circ} C

+ 0.28

E_{c e l l} = E {_{c e l l}}^{0} + \frac{0.059}{2} l o g \frac{[C u^{2 +}]}{[Z n^{2 +}]}

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