You visited us 3 times! Enjoying our articles? Unlock Full Access!

Le Chatelier's Principle for Del N Equals to 0

To the equili...

Question

To the equilibrium system $P C l_{5} (g) ⇌ P C l_{3} (g) + C l_{2} (g)$ , gaseous $C l_{2}$ is added, increasing the volume at the same time in such a manner so that $P C l_{3}$ in the system remains unchanged temperature remains constant what happens to the equilibrium ?

Shifted backward

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Remains unaffected

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Shifted forward

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Depends on the magnitude of

P C l_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B Remains unaffected
Adding $C l_{2}$ shifts the equilibrium backwards, but increasing the volume decreases the pressure thus equilibrium shift in forward direction, thus the effect is canceled mutually, thus $P C l_{3}$ remains unchanged.

Suggest Corrections

Similar questions

P C l_{5} (g) ⇌ P C l_{3} (g) + C l_{2} (g)

C O C l_{2} (g) ⇌ C O (g) + C l_{2} (g)

C O

P {C l}_{5}, P {C l}_{3}

{C l}_{2}

0.5 \times 10^{- 3} M

P {C l}_{3}

1.5 \times 10^{- 2}

P {C l}_{3}

3 \times 10^{- 2} M

{C l}_{2}

K_{c}

P {C l}_{5} (g) ⇌ P {C l}_{3} (g) + {C l}_{2} (g)

P {C l}_{5} (g) ⇌ P {C l}_{3} (g) + {C l}_{2} (g)

{C l}_{2}

P C l_{5} (g) ⇌ P C l_{3} (g) + C l_{2} (g)

C l_{2}

P C l_{5} (g) ⇌ P C l_{3} (g) + C l_{2} (g)

C O (g) + C l_{2} (g) ⇌ C O C l_{2} (g)

N i (s)

N i (C O)_{4} (g)

Join BYJU'S Learning Program